0,4m^2-1=0

Solution for 0,4m^2-1=0 equation:

0.4m^2-1=0

a = 0.4; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·0.4·(-1)
Δ = 1.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.6}}{2*0.4}=\frac{0-\sqrt{1.6}}{0.8}
=-\frac{\sqrt{}}{0.8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.6}}{2*0.4}=\frac{0+\sqrt{1.6}}{0.8}
=\frac{\sqrt{}}{0.8}
$